-.324x^2+7x-36=0

Solution for -.324x^2+7x-36=0 equation:

-.324x^2+7x-36=0

We add all the numbers together, and all the variables

-0.324x^2+7x-36=0

a = -0.324; b = 7; c = -36;
Δ = b2-4ac
Δ = 72-4·(-0.324)·(-36)
Δ = 2.344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2.344}}{2*-0.324}=\frac{-7-\sqrt{2.344}}{-0.648}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2.344}}{2*-0.324}=\frac{-7+\sqrt{2.344}}{-0.648}
$